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Session gmail login separated in two webview diferent Options
Rafael Lucena
Posted: Tuesday, November 11, 2014 4:00:24 PM
Rank: Newbie
Groups: Member

Joined: 11/5/2014
Posts: 8
Hi,
I'm doing the following test:
I created two buttons on the form. Each button opens a different form. Each form has a web view and webcontrol.
test 1
When I start the program I click the button I click on button 1 and 2. When I open gmail in the webview and I log Form1, Form2 also automatically logs. They share the same session.
test 2
If I open the program set up twice, and open a web view on each, they do not share the same session.

What changes should I make in the program code for the test1 it tab webview without two share the same login in gmail?

How do I create two webview in the same program without them share the same login in gmail?
eo_support
Posted: Tuesday, November 11, 2014 4:06:18 PM
Rank: Administration
Groups: Administration

Joined: 5/27/2007
Posts: 24,088
Hi,

In order to prevent the two WebView from sharing sessions/cookies you need to create the two WebView in separate AppDomain. All WebView instance in the same AppDomain will always share cookie/session information.

Thanks!
Rafael Lucena
Posted: Tuesday, November 11, 2014 5:11:21 PM
Rank: Newbie
Groups: Member

Joined: 11/5/2014
Posts: 8
thaaannnnkkkkssss! its work.

Code: C#
public sealed class Isolated<T> : IDisposable where T : MarshalByRefObject
    {
        private AppDomain _domain;
        private T _value;

        public Isolated()
        {
            _domain = AppDomain.CreateDomain("Isolated:" + Guid.NewGuid(),
               null, AppDomain.CurrentDomain.SetupInformation);

            Type type = typeof(T);

            _value = (T)_domain.CreateInstanceAndUnwrap(type.Assembly.FullName, type.FullName);
        }

        public T Value
        {
            get
            {
                return _value;
            }
        }

        public void Dispose()
        {
            if (_domain != null)
            {
                AppDomain.Unload(_domain);

                _domain = null;
            }
        }
    }


Code: C#
using (Isolated<Form2> isolated = new Isolated<Form2>())
            {
                isolated.Value.ShowDialog();
            }
eo_support
Posted: Tuesday, November 11, 2014 9:04:44 PM
Rank: Administration
Groups: Administration

Joined: 5/27/2007
Posts: 24,088
Great. Thanks for sharing! Glad to hear that it works!


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